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sql intersect语句/运算符用于组合两个 select 语句,但仅返回两个select 语句结果集的交集。也就是第一个 select 语句中与第二个 select 语句中相同的行。
与 union 运算符一样,intersect 运算符具有相同的规则。mysql 不支持 intersect 运算符。
intersect的基本语法如下。
select column1 [, column2 ]
from table1 [, table2 ]
[where condition]
intersect
select column1 [, column2 ]
from table1 [, table2 ]
[where condition]
现在我们看如下的两张表
---- ---------- ----- ----------- ----------
| id | name | age | address | salary |
---- ---------- ----- ----------- ----------
| 1 | ramesh | 32 | ahmedabad | 2000.00 |
| 2 | khilan | 25 | delhi | 1500.00 |
| 3 | kaushik | 23 | kota | 2000.00 |
| 4 | chaitali | 25 | mumbai | 6500.00 |
| 5 | hardik | 27 | bhopal | 8500.00 |
| 6 | komal | 22 | mp | 4500.00 |
| 7 | muffy | 24 | indore | 10000.00 |
---- ---------- ----- ----------- ----------
----- --------------------- ------------- --------
|oid | date | customer_id | amount |
----- --------------------- ------------- --------
| 102 | 2009-10-08 00:00:00 | 3 | 3000 |
| 100 | 2009-10-08 00:00:00 | 3 | 1500 |
| 101 | 2009-11-20 00:00:00 | 2 | 1560 |
| 103 | 2008-05-20 00:00:00 | 4 | 2060 |
----- --------------------- ------------- --------
现在,让我们在 select 语句中连接这两个表,如下所示。
sql> select id, name, amount, date
from customers
left join orders
on customers.id = orders.customer_id
intersect
select id, name, amount, date
from customers
right join orders
on customers.id = orders.customer_id;
结果如下。
------ --------- -------- ---------------------
| id | name | amount | date |
------ --------- -------- ---------------------
| 3 | kaushik | 3000 | 2009-10-08 00:00:00 |
| 3 | kaushik | 1500 | 2009-10-08 00:00:00 |
| 2 | ramesh | 1560 | 2009-11-20 00:00:00 |
| 4 | kaushik | 2060 | 2008-05-20 00:00:00 |
------ --------- -------- ---------------------